Integrand size = 37, antiderivative size = 37 \[ \int (g \cos (e+f x))^{-1-m} (a+b \sin (e+f x))^m (A+B \sin (e+f x)) \, dx=\text {Int}\left ((g \cos (e+f x))^{-1-m} (a+b \sin (e+f x))^m (A+B \sin (e+f x)),x\right ) \]
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Not integrable
Time = 0.07 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.00, number of steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int (g \cos (e+f x))^{-1-m} (a+b \sin (e+f x))^m (A+B \sin (e+f x)) \, dx=\int (g \cos (e+f x))^{-1-m} (a+b \sin (e+f x))^m (A+B \sin (e+f x)) \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int (g \cos (e+f x))^{-1-m} (a+b \sin (e+f x))^m (A+B \sin (e+f x)) \, dx \\ \end{align*}
Not integrable
Time = 7.99 (sec) , antiderivative size = 39, normalized size of antiderivative = 1.05 \[ \int (g \cos (e+f x))^{-1-m} (a+b \sin (e+f x))^m (A+B \sin (e+f x)) \, dx=\int (g \cos (e+f x))^{-1-m} (a+b \sin (e+f x))^m (A+B \sin (e+f x)) \, dx \]
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Not integrable
Time = 0.99 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.00
\[\int \left (g \cos \left (f x +e \right )\right )^{-1-m} \left (a +b \sin \left (f x +e \right )\right )^{m} \left (A +B \sin \left (f x +e \right )\right )d x\]
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Not integrable
Time = 0.29 (sec) , antiderivative size = 39, normalized size of antiderivative = 1.05 \[ \int (g \cos (e+f x))^{-1-m} (a+b \sin (e+f x))^m (A+B \sin (e+f x)) \, dx=\int { {\left (B \sin \left (f x + e\right ) + A\right )} \left (g \cos \left (f x + e\right )\right )^{-m - 1} {\left (b \sin \left (f x + e\right ) + a\right )}^{m} \,d x } \]
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Not integrable
Time = 77.17 (sec) , antiderivative size = 36, normalized size of antiderivative = 0.97 \[ \int (g \cos (e+f x))^{-1-m} (a+b \sin (e+f x))^m (A+B \sin (e+f x)) \, dx=\int \left (g \cos {\left (e + f x \right )}\right )^{- m - 1} \left (A + B \sin {\left (e + f x \right )}\right ) \left (a + b \sin {\left (e + f x \right )}\right )^{m}\, dx \]
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Not integrable
Time = 5.89 (sec) , antiderivative size = 39, normalized size of antiderivative = 1.05 \[ \int (g \cos (e+f x))^{-1-m} (a+b \sin (e+f x))^m (A+B \sin (e+f x)) \, dx=\int { {\left (B \sin \left (f x + e\right ) + A\right )} \left (g \cos \left (f x + e\right )\right )^{-m - 1} {\left (b \sin \left (f x + e\right ) + a\right )}^{m} \,d x } \]
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Not integrable
Time = 1.17 (sec) , antiderivative size = 39, normalized size of antiderivative = 1.05 \[ \int (g \cos (e+f x))^{-1-m} (a+b \sin (e+f x))^m (A+B \sin (e+f x)) \, dx=\int { {\left (B \sin \left (f x + e\right ) + A\right )} \left (g \cos \left (f x + e\right )\right )^{-m - 1} {\left (b \sin \left (f x + e\right ) + a\right )}^{m} \,d x } \]
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Not integrable
Time = 14.32 (sec) , antiderivative size = 39, normalized size of antiderivative = 1.05 \[ \int (g \cos (e+f x))^{-1-m} (a+b \sin (e+f x))^m (A+B \sin (e+f x)) \, dx=\int \frac {\left (A+B\,\sin \left (e+f\,x\right )\right )\,{\left (a+b\,\sin \left (e+f\,x\right )\right )}^m}{{\left (g\,\cos \left (e+f\,x\right )\right )}^{m+1}} \,d x \]
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